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Practice Problems In Physics Abhay Kumar Pdf Guide

$0 = (20)^2 - 2(9.8)h$

At $t = 2$ s, $a = 6(2) - 2 = 12 - 2 = 10$ m/s$^2$ practice problems in physics abhay kumar pdf

Using $v^2 = u^2 - 2gh$, we get

At maximum height, $v = 0$